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TRIANGLE INEQUALITY property. THE SUM OF THE LENGTH OF TWO SIDES OF A TRIANGLE IS ALWAYS GREATER THAN THE THIRD SIDE. LIKE IN THE △ABC , IN WHICH AB + BC > AC BC + AC > AB AB + AC > BC.
IN CASE 1. TAKE SIDE AB = 2cm , BC = 3cm , AC = 5cm NOW ADD AB + BC > AC 2 + 3 > 5 5 = 5 SO IT WILL NOT FORM A TRIANGLE BECAUSE LHS = RHS.
IN CASE 2. TAKE SIDE AB = 6cm , BC = 3cm , AC = 2cm NOW ADD THESE AB + BC > AC 6 + 3 > 2 9 > 2 SO THE SUM AB AND BC IS GREATER THAN AC..
NOW ADD BC + AC > AB 3cm + 2cm > 6cm 5cm > 6cm THE SUM IS SMALLER. SO, IT WILL NOT FORMED A TRIANGLE..
IN CASE 3. TAKE SIDES AB = 3cm , BC = 6cm , CA = 7cm NOW ADD AB + BC > CA 3cm + 6cm > 7cm 9cm > 7cm THE SUM IS GREATER.
NOW TAKE NOW TAKE BC + CA > AB CA + AB > BC 6 + 7 > 3cm 7 + 3 > 6 13 > 3 10 > 6 SO THE SUM IS GREATER. SO, THE SUM IS GREATER SUM OF ALL THE SIDES ARE GREATER THAN THIRD SIDE . SO IT WILL FORM A TRIANGLE..
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Loujain Labban 9GB Maths Assessment 2016 | Math | ShowMe.